implemented linked list

This commit is contained in:
not why 2026-05-25 00:36:56 +03:00
parent 82e988c965
commit 72d2269634

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@ -0,0 +1,53 @@
# 1. СВЯЗНЫЙ СПИСОК
def ll_create_node(name, phone):
return {'name': name, 'phone': phone, 'next': None}
def ll_insert(head, name, phone):
"""Добавить или обновить запись. Возвращает голову списка."""
node = head
while node is not None:
if node['name'] == name:
node['phone'] = phone # обновить
return head
node = node['next']
# Вставка в начало — O(1)
new_node = ll_create_node(name, phone)
new_node['next'] = head
return new_node
def ll_find(head, name):
"""Вернуть телефон или None."""
node = head
while node is not None:
if node['name'] == name:
return node['phone']
node = node['next']
return None
def ll_delete(head, name):
"""Удалить узел, вернуть новую голову."""
if head is None:
return None
if head['name'] == name:
return head['next']
prev, node = head, head['next']
while node is not None:
if node['name'] == name:
prev['next'] = node['next']
return head
prev, node = node, node['next']
return head
def ll_list_all(head):
"""Собрать все записи и вернуть отсортированный список (name, phone)."""
result = []
node = head
while node is not None:
result.append((node['name'], node['phone']))
node = node['next']
result.sort(key=lambda x: x[0])
return result