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2026-rff_mp/MarkinAM/1/structures.py

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Python
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2026-05-25 06:57:30 +00:00
# === 1. Связный список (LinkedList) ===
def ll_insert(head, name, phone):
# Вставка новой записи или обновление существующей
if head is None:
return {'name': name, 'phone': phone, 'next': None}
current = head
# Ищем, есть ли уже запись с этим именем
while current is not None:
if current['name'] == name:
current['phone'] = phone # Обновляем телефон
return head
current = current["next"]
# Если не нашли, добавляем в конец
current = head
while current['next'] is not None:
current = current['next']
current['next'] = {'name': name, 'phone': phone, 'next': None}
return head
def ll_find(head, name):
"""Ищет запись по имени, возвращает телефон или None."""
current = head
while current:
if current['name'] == name:
return current['phone']
current = current['next']
return None
def ll_delete(head, name):
current = head
previous = None
while current is not None:
if current['name'] == name:
if previous is None:
return current['next']
previous['next'] = current['next']
return head
previous = current
current = current['next']
return head
def ll_list_all(head):
#Собирает все записи в отсортированный список кортежей.
records = []
current = head
while current:
records.append((current['name'], current['phone']))
current = current['next']
# Сортируем по имени
return sorted(records, key=lambda x: x[0])
# === 2. Хеш-таблица (HashTable) ===
def my_hash(s, M):
B = 31
n = len(s)
h = 0
for i in range(n):
h += ord(s[i]) * (B ** (n - 1 - i))
return h % M
def ht_insert(buckets, name, phone):
index = my_hash(name, len(buckets))
# Вставляем в соответствующий бакет
buckets[index] = ll_insert(buckets[index], name, phone)
return buckets
def ht_find(buckets, name):
index = my_hash(name, len(buckets))
# Ищем внутри бакета
return ll_find(buckets[index], name)
def ht_delete(buckets, name):
index = my_hash(name, len(buckets))
# Удаляем внутри бакета
buckets[index] = ll_delete(buckets[index], name)
return buckets
def ht_list_all(buckets):
# Собираем все записи из бакетов
result = []
for i in range(len(buckets)):
result += ll_list_all(buckets[i])
# Сортируем по имени
result.sort(key=lambda x: x[0])
return result
# === 3. Двоичное дерево поиска (BST) ===
def bst_insert(root, name, phone):
if root is None:
return {'name': name, 'phone': phone,'left': None, 'right': None}
current = root
while True:
# если такое имя уже есть — меняем телефон
if name == current['name']:
current['phone'] = phone
return root
# если новое имя меньше — идём влево
if name < current['name']:
if current['left'] is None:
current['left'] = {'name': name, 'phone': phone,'left': None, 'right': None}
return root
current = current['left']
# если новое имя больше — идём вправо
else:
if current['right'] is None:
current['right'] = {'name': name, 'phone': phone,'left': None, 'right': None}
return root
current = current['right']
def bst_find(root, name):
current = root
while current is not None:
if name == current['name']:
return current['phone']
if name < current['name']:
current = current['left']
else:
current = current['right']
return None
def bst_delete(root, name):
current = root
previous = None
while current is not None and current['name'] != name:
previous = current
if name < current['name']:
current = current['left']
else:
current = current['right']
# если не нашли
if current is None:
return root
# 2. Если у узла два потомка
if current['left'] is not None and current['right'] is not None:
successor_parent = current
successor = current['right']
# ищем минимальный узел в правом поддереве
while successor['left'] is not None:
successor_parent = successor
successor = successor['left']
# копируем данные successor в current
current['name'] = successor['name']
current['phone'] = successor['phone']
# теперь удаляем successor
current = successor
previous = successor_parent
#3
if current['left'] is not None:
child = current['left']
else:
child = current['right']
# 4. Если удаляем корень
if previous is None:
return child
# 5. Переподключаем родителя
if previous['left'] is current:
previous['left'] = child
else:
previous['right'] = child
return root
def bst_list_all(root):
result = []
def inorder(node):
if node is None:
return
inorder(node['left'])
result.append((node['name'], node['phone']))
inorder(node['right'])
inorder(root)
return result