68 lines
2.1 KiB
Plaintext
68 lines
2.1 KiB
Plaintext
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{
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"cells": [
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{
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"cell_type": "code",
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"execution_count": null,
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"id": "3f8f5923-00bf-4fc2-88e9-6a51d6183c5b",
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"metadata": {},
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"outputs": [],
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"source": [
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"from abc import ABC, abstractmethod\n",
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"from typing import List, Optional\n",
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"from modelsMaze import Maze\n",
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"from modelsCell import Cell\n",
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"\n",
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"class PathFindingStrategy(ABC):\n",
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" \"\"\"Интерфейс стратегии поиска пути (паттерн Strategy).\"\"\"\n",
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" \n",
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" @abstractmethod\n",
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" def find_path(self, maze: Maze, start: Cell, exit_cell: Cell) -> List[Cell]:\n",
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" \"\"\"\n",
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" Найти путь от start до exit_cell.\n",
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" Возвращает список клеток пути (включая start и exit) или пустой список.\n",
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" \"\"\"\n",
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" pass\n",
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" \n",
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" @property\n",
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" @abstractmethod\n",
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" def name(self) -> str:\n",
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" \"\"\"Имя стратегии для отчётов.\"\"\"\n",
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" pass\n",
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" \n",
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" def _reconstruct_path(self, came_from: dict, start: Cell, current: Cell) -> List[Cell]:\n",
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" \"\"\"Восстановить путь из словаря предков.\"\"\"\n",
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" path = []\n",
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" while current != start:\n",
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" path.append(current)\n",
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" current = came_from.get(current)\n",
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" if current is None:\n",
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" return []\n",
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" path.append(start)\n",
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" path.reverse()\n",
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" return path"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python [conda env:base] *",
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"language": "python",
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"name": "conda-base-py"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.13.9"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 5
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}
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