forked from UNN/2026-rff_mp
198 lines
5.7 KiB
Python
198 lines
5.7 KiB
Python
# === 1. Связный список (LinkedList) ===
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def ll_insert(head, name, phone):
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# Вставка новой записи или обновление существующей
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if head is None:
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return {'name': name, 'phone': phone, 'next': None}
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current = head
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# Ищем, есть ли уже запись с этим именем
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while current is not None:
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if current['name'] == name:
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current['phone'] = phone # Обновляем телефон
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return head
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current = current["next"]
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# Если не нашли, добавляем в конец
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current = head
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while current['next'] is not None:
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current = current['next']
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current['next'] = {'name': name, 'phone': phone, 'next': None}
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return head
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def ll_find(head, name):
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"""Ищет запись по имени, возвращает телефон или None."""
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current = head
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while current:
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if current['name'] == name:
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return current['phone']
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current = current['next']
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return None
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def ll_delete(head, name):
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current = head
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previous = None
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while current is not None:
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if current['name'] == name:
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if previous is None:
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return current['next']
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previous['next'] = current['next']
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return head
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previous = current
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current = current['next']
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return head
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def ll_list_all(head):
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#Собирает все записи в отсортированный список кортежей.
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records = []
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current = head
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while current:
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records.append((current['name'], current['phone']))
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current = current['next']
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# Сортируем по имени
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return sorted(records, key=lambda x: x[0])
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# === 2. Хеш-таблица (HashTable) ===
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def my_hash(s, M):
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B = 31
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n = len(s)
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h = 0
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for i in range(n):
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h += ord(s[i]) * (B ** (n - 1 - i))
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return h % M
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def ht_insert(buckets, name, phone):
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index = my_hash(name, len(buckets))
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# Вставляем в соответствующий бакет
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buckets[index] = ll_insert(buckets[index], name, phone)
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return buckets
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def ht_find(buckets, name):
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index = my_hash(name, len(buckets))
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# Ищем внутри бакета
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return ll_find(buckets[index], name)
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def ht_delete(buckets, name):
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index = my_hash(name, len(buckets))
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# Удаляем внутри бакета
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buckets[index] = ll_delete(buckets[index], name)
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return buckets
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def ht_list_all(buckets):
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# Собираем все записи из бакетов
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result = []
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for i in range(len(buckets)):
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result += ll_list_all(buckets[i])
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# Сортируем по имени
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result.sort(key=lambda x: x[0])
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return result
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# === 3. Двоичное дерево поиска (BST) ===
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def bst_insert(root, name, phone):
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if root is None:
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return {'name': name, 'phone': phone,'left': None, 'right': None}
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current = root
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while True:
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# если такое имя уже есть — меняем телефон
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if name == current['name']:
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current['phone'] = phone
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return root
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# если новое имя меньше — идём влево
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if name < current['name']:
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if current['left'] is None:
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current['left'] = {'name': name, 'phone': phone,'left': None, 'right': None}
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return root
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current = current['left']
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# если новое имя больше — идём вправо
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else:
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if current['right'] is None:
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current['right'] = {'name': name, 'phone': phone,'left': None, 'right': None}
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return root
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current = current['right']
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def bst_find(root, name):
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current = root
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while current is not None:
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if name == current['name']:
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return current['phone']
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if name < current['name']:
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current = current['left']
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else:
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current = current['right']
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return None
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def bst_delete(root, name):
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current = root
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previous = None
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while current is not None and current['name'] != name:
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previous = current
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if name < current['name']:
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current = current['left']
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else:
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current = current['right']
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# если не нашли
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if current is None:
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return root
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# 2. Если у узла два потомка
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if current['left'] is not None and current['right'] is not None:
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successor_parent = current
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successor = current['right']
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# ищем минимальный узел в правом поддереве
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while successor['left'] is not None:
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successor_parent = successor
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successor = successor['left']
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# копируем данные successor в current
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current['name'] = successor['name']
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current['phone'] = successor['phone']
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# теперь удаляем successor
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current = successor
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previous = successor_parent
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#3
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if current['left'] is not None:
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child = current['left']
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else:
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child = current['right']
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# 4. Если удаляем корень
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if previous is None:
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return child
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# 5. Переподключаем родителя
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if previous['left'] is current:
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previous['left'] = child
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else:
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previous['right'] = child
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return root
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def bst_list_all(root):
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result = []
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def inorder(node):
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if node is None:
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return
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inorder(node['left'])
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result.append((node['name'], node['phone']))
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inorder(node['right'])
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inorder(root)
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return result |