forked from UNN/2026-rff_mp
198 lines
5.7 KiB
Python
198 lines
5.7 KiB
Python
|
|
# === 1. Связный список (LinkedList) ===
|
|||
|
|
|
|||
|
|
def ll_insert(head, name, phone):
|
|||
|
|
# Вставка новой записи или обновление существующей
|
|||
|
|
if head is None:
|
|||
|
|
return {'name': name, 'phone': phone, 'next': None}
|
|||
|
|
|
|||
|
|
current = head
|
|||
|
|
# Ищем, есть ли уже запись с этим именем
|
|||
|
|
while current is not None:
|
|||
|
|
if current['name'] == name:
|
|||
|
|
current['phone'] = phone # Обновляем телефон
|
|||
|
|
return head
|
|||
|
|
current = current["next"]
|
|||
|
|
|
|||
|
|
# Если не нашли, добавляем в конец
|
|||
|
|
current = head
|
|||
|
|
while current['next'] is not None:
|
|||
|
|
current = current['next']
|
|||
|
|
current['next'] = {'name': name, 'phone': phone, 'next': None}
|
|||
|
|
return head
|
|||
|
|
|
|||
|
|
def ll_find(head, name):
|
|||
|
|
"""Ищет запись по имени, возвращает телефон или None."""
|
|||
|
|
current = head
|
|||
|
|
while current:
|
|||
|
|
if current['name'] == name:
|
|||
|
|
return current['phone']
|
|||
|
|
current = current['next']
|
|||
|
|
return None
|
|||
|
|
|
|||
|
|
def ll_delete(head, name):
|
|||
|
|
current = head
|
|||
|
|
previous = None
|
|||
|
|
|
|||
|
|
while current is not None:
|
|||
|
|
if current['name'] == name:
|
|||
|
|
if previous is None:
|
|||
|
|
return current['next']
|
|||
|
|
previous['next'] = current['next']
|
|||
|
|
return head
|
|||
|
|
previous = current
|
|||
|
|
current = current['next']
|
|||
|
|
return head
|
|||
|
|
|
|||
|
|
def ll_list_all(head):
|
|||
|
|
#Собирает все записи в отсортированный список кортежей.
|
|||
|
|
records = []
|
|||
|
|
current = head
|
|||
|
|
while current:
|
|||
|
|
records.append((current['name'], current['phone']))
|
|||
|
|
current = current['next']
|
|||
|
|
# Сортируем по имени
|
|||
|
|
return sorted(records, key=lambda x: x[0])
|
|||
|
|
|
|||
|
|
|
|||
|
|
# === 2. Хеш-таблица (HashTable) ===
|
|||
|
|
|
|||
|
|
def my_hash(s, M):
|
|||
|
|
B = 31
|
|||
|
|
n = len(s)
|
|||
|
|
h = 0
|
|||
|
|
for i in range(n):
|
|||
|
|
h += ord(s[i]) * (B ** (n - 1 - i))
|
|||
|
|
return h % M
|
|||
|
|
|
|||
|
|
def ht_insert(buckets, name, phone):
|
|||
|
|
index = my_hash(name, len(buckets))
|
|||
|
|
# Вставляем в соответствующий бакет
|
|||
|
|
buckets[index] = ll_insert(buckets[index], name, phone)
|
|||
|
|
return buckets
|
|||
|
|
|
|||
|
|
def ht_find(buckets, name):
|
|||
|
|
index = my_hash(name, len(buckets))
|
|||
|
|
# Ищем внутри бакета
|
|||
|
|
return ll_find(buckets[index], name)
|
|||
|
|
|
|||
|
|
def ht_delete(buckets, name):
|
|||
|
|
index = my_hash(name, len(buckets))
|
|||
|
|
# Удаляем внутри бакета
|
|||
|
|
buckets[index] = ll_delete(buckets[index], name)
|
|||
|
|
return buckets
|
|||
|
|
|
|||
|
|
def ht_list_all(buckets):
|
|||
|
|
# Собираем все записи из бакетов
|
|||
|
|
result = []
|
|||
|
|
for i in range(len(buckets)):
|
|||
|
|
result += ll_list_all(buckets[i])
|
|||
|
|
# Сортируем по имени
|
|||
|
|
result.sort(key=lambda x: x[0])
|
|||
|
|
return result
|
|||
|
|
|
|||
|
|
|
|||
|
|
# === 3. Двоичное дерево поиска (BST) ===
|
|||
|
|
|
|||
|
|
def bst_insert(root, name, phone):
|
|||
|
|
if root is None:
|
|||
|
|
return {'name': name, 'phone': phone,'left': None, 'right': None}
|
|||
|
|
|
|||
|
|
current = root
|
|||
|
|
while True:
|
|||
|
|
# если такое имя уже есть — меняем телефон
|
|||
|
|
if name == current['name']:
|
|||
|
|
current['phone'] = phone
|
|||
|
|
return root
|
|||
|
|
|
|||
|
|
# если новое имя меньше — идём влево
|
|||
|
|
if name < current['name']:
|
|||
|
|
if current['left'] is None:
|
|||
|
|
current['left'] = {'name': name, 'phone': phone,'left': None, 'right': None}
|
|||
|
|
return root
|
|||
|
|
current = current['left']
|
|||
|
|
|
|||
|
|
# если новое имя больше — идём вправо
|
|||
|
|
else:
|
|||
|
|
if current['right'] is None:
|
|||
|
|
current['right'] = {'name': name, 'phone': phone,'left': None, 'right': None}
|
|||
|
|
return root
|
|||
|
|
current = current['right']
|
|||
|
|
|
|||
|
|
def bst_find(root, name):
|
|||
|
|
current = root
|
|||
|
|
|
|||
|
|
while current is not None:
|
|||
|
|
if name == current['name']:
|
|||
|
|
return current['phone']
|
|||
|
|
|
|||
|
|
if name < current['name']:
|
|||
|
|
current = current['left']
|
|||
|
|
else:
|
|||
|
|
current = current['right']
|
|||
|
|
|
|||
|
|
return None
|
|||
|
|
|
|||
|
|
def bst_delete(root, name):
|
|||
|
|
current = root
|
|||
|
|
previous = None
|
|||
|
|
|
|||
|
|
while current is not None and current['name'] != name:
|
|||
|
|
previous = current
|
|||
|
|
|
|||
|
|
if name < current['name']:
|
|||
|
|
current = current['left']
|
|||
|
|
else:
|
|||
|
|
current = current['right']
|
|||
|
|
|
|||
|
|
# если не нашли
|
|||
|
|
if current is None:
|
|||
|
|
return root
|
|||
|
|
|
|||
|
|
# 2. Если у узла два потомка
|
|||
|
|
if current['left'] is not None and current['right'] is not None:
|
|||
|
|
successor_parent = current
|
|||
|
|
successor = current['right']
|
|||
|
|
|
|||
|
|
# ищем минимальный узел в правом поддереве
|
|||
|
|
while successor['left'] is not None:
|
|||
|
|
successor_parent = successor
|
|||
|
|
successor = successor['left']
|
|||
|
|
|
|||
|
|
# копируем данные successor в current
|
|||
|
|
current['name'] = successor['name']
|
|||
|
|
current['phone'] = successor['phone']
|
|||
|
|
|
|||
|
|
# теперь удаляем successor
|
|||
|
|
current = successor
|
|||
|
|
previous = successor_parent
|
|||
|
|
#3
|
|||
|
|
if current['left'] is not None:
|
|||
|
|
child = current['left']
|
|||
|
|
else:
|
|||
|
|
child = current['right']
|
|||
|
|
|
|||
|
|
# 4. Если удаляем корень
|
|||
|
|
if previous is None:
|
|||
|
|
return child
|
|||
|
|
|
|||
|
|
# 5. Переподключаем родителя
|
|||
|
|
if previous['left'] is current:
|
|||
|
|
previous['left'] = child
|
|||
|
|
else:
|
|||
|
|
previous['right'] = child
|
|||
|
|
|
|||
|
|
return root
|
|||
|
|
|
|||
|
|
def bst_list_all(root):
|
|||
|
|
result = []
|
|||
|
|
|
|||
|
|
def inorder(node):
|
|||
|
|
if node is None:
|
|||
|
|
return
|
|||
|
|
|
|||
|
|
inorder(node['left'])
|
|||
|
|
result.append((node['name'], node['phone']))
|
|||
|
|
inorder(node['right'])
|
|||
|
|
|
|||
|
|
inorder(root)
|
|||
|
|
return result
|